Find the least number to be added to 2010 to make it divisiable by 19

Lets divide 2010 by 19 we get a Quotient of 105 and remainder of 15

Now this remainder is 4 short of getting perfectly divisible by 19 i.e. if our remainder was (15+4=19) we would have got full divisibility.

So if we add 4 to 2010 it would be fully divisible by 19 hence answer is 4.